Y^2-24+144=(y-12)(y-12)

Solution for Y^2-24+144=(y-12)(y-12) equation:

^2-24+144=(Y-12)(Y-12)

We move all terms to the left:

^2-24+144-((Y-12)(Y-12))=0

We add all the numbers together, and all the variables

-((Y-12)(Y-12))=0

We multiply parentheses ..

-((+Y^2-12Y-12Y+144))=0


We calculate terms in parentheses: -((+Y^2-12Y-12Y+144)), so:

(+Y^2-12Y-12Y+144)

We get rid of parentheses

Y^2-12Y-12Y+144

We add all the numbers together, and all the variables

Y^2-24Y+144

Back to the equation:

-(Y^2-24Y+144)


We get rid of parentheses

-Y^2+24Y-144=0

We add all the numbers together, and all the variables

-1Y^2+24Y-144=0

a = -1; b = 24; c = -144;
Δ = b2-4ac
Δ = 242-4·(-1)·(-144)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Y=\frac{-b}{2a}=\frac{-24}{-2}=+12$